Last updated: 2017-03-04
Code version: 5d0fa13282db4a97dc7d62e2d704e88a5afdb824
You should know what a Bayes Factor is and what a p value is.
Sellke et al (Thomas Sellke 2001) study the following question (paraphrased and shortened here).
Consider the situation in which experimental drugs D1; D2; D3; etc are to be tested. Each test will be thought of as completely independent; we simply have a series of tests so that we can explore the frequentist properties of p values. In each test, the following hypotheses are to be tested: H0:Di has negligible effect versus H1:Di has a non-negligible effect.
Suppose that one of these tests results in a p value ≈p. The question we consider is: How strong is the evidence that the drug in question has a non-negligible effect?
The answer to this question has to depend on the distribution of effects under H1. However, Sellke et al derive a bound for the Bayes Factor. Specifically they show that, provided p<1/e, the BF in favor of H1 is not larger than 1/B(p)=−[eplog(p)]−1. (Note: the inverse comes from the fact that here we consider the BF in favor of H1, whereas Sellke et al consider the BF in favor of H_0).
Here we illustrate this result using Bayes Theorem to do calculations under a simple scenario.
Let θi denote the effect of drug Di. We will translate the null H0 above to mean θi=0. We will also make an assumption that the effects of the non-null drugs are normally distributed N(0,σ2), where the value of σ determines how different the typical effect is from 0.
Thus we have: H0i:θi=0 H1i:θi∼N(0,σ2).
In addition we will assume that we have data (e.g. the results of a drug trial) that give us imperfect information about θ. Specifically we assume Xi|θi∼N(θi,1). This implies that: Xi|H0i∼N(0,1) Xi|H1i∼N(0,1+σ2)
Consequently the Bayes Factor (BF) comparing H1 vs H0 can be computed as follows:
BF= function(x,s){dnorm(x,0,sqrt(s^2+1))/dnorm(x,0,1)}
Of course the BF depends both on the data x and the choice of σ (here s
in the code).
We can plot this BF for x=1.96 (which is the value for which p=0.05):
s = seq(0,10,length=100)
plot(s,BF(1.96,s),xlab="sigma",ylab="BF at p=0.05",type="l",ylim=c(0,4))
BFbound=function(p){1/(-exp(1)*p*log(p))}
abline(h=BFbound(0.05),col=2)
Here the horizontal line shows the bound on the Bayes Factor computed by Sellke et al.
And here is the same plot for x=2.58 (p=0.01):
plot(s,BF(2.58,s),xlab="sigma",ylab="BF at p=0.01",type="l",ylim=c(0,10))
abline(h=BFbound(0.01),col=2)
Note some key features:
sessionInfo()
R version 3.3.0 (2016-05-03)
Platform: x86_64-apple-darwin13.4.0 (64-bit)
Running under: OS X 10.10.5 (Yosemite)
locale:
[1] en_NZ.UTF-8/en_NZ.UTF-8/en_NZ.UTF-8/C/en_NZ.UTF-8/en_NZ.UTF-8
attached base packages:
[1] stats graphics grDevices utils datasets methods base
other attached packages:
[1] tidyr_0.4.1 dplyr_0.5.0 ggplot2_2.1.0 knitr_1.15.1
[5] MASS_7.3-45 expm_0.999-0 Matrix_1.2-6 viridis_0.3.4
[9] workflowr_0.3.0 rmarkdown_1.3
loaded via a namespace (and not attached):
[1] Rcpp_0.12.5 git2r_0.18.0 plyr_1.8.4 tools_3.3.0
[5] digest_0.6.9 evaluate_0.10 tibble_1.1 gtable_0.2.0
[9] lattice_0.20-33 shiny_0.13.2 DBI_0.4-1 yaml_2.1.14
[13] gridExtra_2.2.1 stringr_1.2.0 gtools_3.5.0 rprojroot_1.2
[17] grid_3.3.0 R6_2.1.2 reshape2_1.4.1 magrittr_1.5
[21] backports_1.0.5 scales_0.4.0 htmltools_0.3.5 assertthat_0.1
[25] mime_0.5 colorspace_1.2-6 xtable_1.8-2 httpuv_1.3.3
[29] labeling_0.3 stringi_1.1.2 munsell_0.4.3
Thomas Sellke, James O. Berger, M. J. Bayarri. 2001. “Calibration of p Values for Testing Precise Null Hypothesis.” The American Statistician 55 (1).
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